Milwaukee Bucks and Oklahoma City Thunder in the NBA Cup final

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LAS VEGAS (USA) (ITALPRESS) – Milwaukee and Oklahoma City will play for the NBA Cup. Bucks and Thunder have overcome Atlanta and
Houston in Las Vegas earning the right to play in the
night between Tuesday and Wednesday, the last act of the tournament.
In the first semi-final, Giannis Antetokounmpo leads the way
once again Milwaukee wins 110-102: best
NBA scorer this season (32.7 points per game).
match), the Greek ace scored his fifth match in a row with
at least 30 points. 32 in this circumstance against the Hawks, accompanied by 14 rebounds and 9 assists. Trae Young’s 35 points, 10 assists and 7 rebounds were not enough for Atlanta.
Milwaukee will therefore challenge Oklahoma, which they find at the T-Mobile Arena
once again in Shai Gilgeous-Alexander his ace: 32 points
(plus 8 rebounds and six assists) against the Rockets, in a de facto match
only for half the match and defeated 111-96. Gilgeous-Alexander has
found valuable allies in Isaiah Hartenstein (21 points), Jalen
Williams (20) and Luguentz Dort (19).

– Ipa Agency photo –
(ITALPRESS).

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